Difference between revisions of "2014 UNM-PNM Statewide High School Mathematics Contest II Problems/Problem 1"
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<math>r-n=4</math> | <math>r-n=4</math> | ||
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<math>r=n+4</math> | <math>r=n+4</math> | ||
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<math>s+2a+n+4+h=18</math>. | <math>s+2a+n+4+h=18</math>. | ||
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<math>s+2a+n+h=14</math>. | <math>s+2a+n+h=14</math>. | ||
This matches the expression we need to solve for, so we are done. <math>\boxed{14}</math>. | This matches the expression we need to solve for, so we are done. <math>\boxed{14}</math>. | ||
+ | |||
+ | |||
+ | ==Slick Solution== | ||
+ | BRYAN, SARAH is an anagram of BARRY, SHANA. Let SHANA be <math>x</math>. So we have the following equation: | ||
+ | <cmath>21+18=25+x\rightarrow \boxed{x=14}</cmath> | ||
+ | |||
+ | ~yofro | ||
== See also == | == See also == |
Latest revision as of 11:55, 4 August 2020
Contents
Problem
Four siblings BRYAN, BARRY, SARAH and SHANA are having their names monogrammed on their towels.
Different letters may cost different amounts to monogram.
If it costs to monogram BRYAN,
to monogram BARRY and
to monogram SARAH,
how much does it cost to monogram SHANA?
Solution
We set up the following equations:
We are asked to find the price of "Shana", or . We notice that this expression has no
or
, so we subtract the first equation from the second to eliminate those variables:
Which we substitute into the third equation
.
.
This matches the expression we need to solve for, so we are done. .
Slick Solution
BRYAN, SARAH is an anagram of BARRY, SHANA. Let SHANA be . So we have the following equation:
~yofro
See also
2014 UNM-PNM Contest II (Problems • Answer Key • Resources) | ||
Preceded by First question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
All UNM-PNM Problems and Solutions |