Difference between revisions of "2002 AMC 8 Problems/Problem 8"
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Problems 8,9 and 10 use the data found in the accompanying paragraph and table: | Problems 8,9 and 10 use the data found in the accompanying paragraph and table: | ||
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label(scale(0.9)*"Juan's Stamp Collection", (9,0), S); | label(scale(0.9)*"Juan's Stamp Collection", (9,0), S); | ||
label(scale(0.9)*"Number of Stamps by Decade", (9,5), N);</asy> | label(scale(0.9)*"Number of Stamps by Decade", (9,5), N);</asy> | ||
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How many of his European stamps were issued in the '80s? | How many of his European stamps were issued in the '80s? | ||
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==Solution== | ==Solution== | ||
− | + | France and Spain are European countries. The number of '80s stamps from France is <math>15</math> and the number of '80s stamps from Spain is <math>9</math>. The total number of stamps is <math>15+9=\boxed{\text{(D)}\ 24}</math>. | |
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+ | ==Video Solution by WhyMath== | ||
+ | https://youtu.be/C6w6ugIDOGw | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2002|num-b=7|num-a=9}} | {{AMC8 box|year=2002|num-b=7|num-a=9}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 13:29, 29 October 2024
Problem
Problems 8,9 and 10 use the data found in the accompanying paragraph and table:
Juan organizes the stamps in his collection by country and by the decade in which they were issued. The prices he paid for them at a stamp shop were: Brazil and France, 6 cents each, Peru 4 cents each, and Spain 5 cents each. (Brazil and Peru are South American countries and France and Spain are in Europe.)
How many of his European stamps were issued in the '80s?
Solution
France and Spain are European countries. The number of '80s stamps from France is and the number of '80s stamps from Spain is . The total number of stamps is .
Video Solution by WhyMath
See Also
2002 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.