Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 10"
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== Problem == | == Problem == | ||
+ | <math>\arcsin\left(\frac{1}{3}\right) + \arccos\left(\frac{1}{3}\right) + \arctan\left(\frac13\right) + \text{arccot}\left(\frac13\right) =</math> | ||
− | <center><math> \mathrm{(A) \ } \qquad \mathrm{(B) \ } \qquad \mathrm{(C) \ } \qquad \mathrm{(D) \ } \qquad \mathrm{(E) \ } </math></center> | + | <center><math> \mathrm{(A) \ }\pi \qquad \mathrm{(B) \ }\pi/2 \qquad \mathrm{(C) \ }\pi/3 \qquad \mathrm{(D) \ }2\pi/3 \qquad \mathrm{(E) \ }3/\pi/4 </math></center> |
== Solution == | == Solution == | ||
+ | If we construct right triangles for each pair of arguments (<math>\arcsin, \arccos</math> in one triangle and <math>\arctan, \text{arccot}</math> in another), we see that the sum of the angles is <math>90^\circ+90^\circ=\pi</math>. | ||
− | + | ---- | |
− | * [[University of South Carolina High School Math Contest/1993 Exam]] | + | |
+ | * [[University of South Carolina High School Math Contest/1993 Exam/Problem 9|Previous Problem]] | ||
+ | * [[University of South Carolina High School Math Contest/1993 Exam/Problem 11|Next Problem]] | ||
+ | * [[University of South Carolina High School Math Contest/1993 Exam|Back to Exam]] | ||
+ | |||
+ | [[Category:Introductory Trigonometry Problems]] |
Latest revision as of 21:15, 31 May 2009
Problem
![$\mathrm{(A) \ }\pi \qquad \mathrm{(B) \ }\pi/2 \qquad \mathrm{(C) \ }\pi/3 \qquad \mathrm{(D) \ }2\pi/3 \qquad \mathrm{(E) \ }3/\pi/4$](http://latex.artofproblemsolving.com/9/7/b/97b0fa52186af1028b00c9f5a690827a039634be.png)
Solution
If we construct right triangles for each pair of arguments ( in one triangle and
in another), we see that the sum of the angles is
.