Difference between revisions of "2000 PMWC Problems/Problem I15"
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==Solution== | ==Solution== | ||
− | Try 5: 2*3*4*5*6 = 720 | + | Try <cmath>5: 2*3*4*5*6 = 720</cmath> |
− | Try 4: 3*4*6*7 = 504 | + | Try <cmath>4: 3*4*6*7 = 504</cmath> |
− | Try 3 | + | Try 3, then realize it's going to be smaller. |
− | 6 numbers is too many | + | 6 numbers is too many, since <cmath>1+2+3+4+5+6=21</cmath> |
+ | Thus the answer is 720 | ||
==See Also== | ==See Also== |
Latest revision as of 13:26, 31 January 2017
Problem
The sum of several positive integers is . Find the largest product that can be formed by these integers.
Solution
Try Try Try 3, then realize it's going to be smaller. 6 numbers is too many, since Thus the answer is 720