Difference between revisions of "2000 PMWC Problems/Problem I15"

(Solution)
(Solution)
 
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==Solution==
 
==Solution==
Try 5: 2*3*4*5*6 = 720
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Try <cmath>5: 2*3*4*5*6 = 720</cmath>
Try 4: 3*4*6*7 = 504
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Try <cmath>4: 3*4*6*7 = 504</cmath>
Try 3...
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Try 3, then realize it's going to be smaller.
6 numbers is too many.
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6 numbers is too many, since <cmath>1+2+3+4+5+6=21</cmath>
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Thus the answer is 720
  
 
==See Also==
 
==See Also==

Latest revision as of 13:26, 31 January 2017

Problem

The sum of several positive integers is $20$. Find the largest product that can be formed by these integers.

Solution

Try \[5: 2*3*4*5*6 = 720\] Try \[4: 3*4*6*7 = 504\] Try 3, then realize it's going to be smaller. 6 numbers is too many, since \[1+2+3+4+5+6=21\] Thus the answer is 720

See Also