Difference between revisions of "1962 AHSME Problems/Problem 29"
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− | + | First, subtract 6 from both sides of the inequality, | |
+ | <math>2x^2 + x - 6 < 0</math>. | ||
+ | This is a parabola that opens upward when graphed, it has a positive leading coefficient. So any negative x values must be between its x-axis intersections, namely <math>x = -2, 1.5</math>. The answer is A. |
Latest revision as of 22:23, 4 June 2018
Problem
Which of the following sets of -values satisfy the inequality
?
Solution
First, subtract 6 from both sides of the inequality,
.
This is a parabola that opens upward when graphed, it has a positive leading coefficient. So any negative x values must be between its x-axis intersections, namely
. The answer is A.