Difference between revisions of "2006 AMC 8 Problems/Problem 1"
m (→Solution) |
|||
| (3 intermediate revisions by 3 users not shown) | |||
| Line 5: | Line 5: | ||
== Solution == | == Solution == | ||
| − | The three prices round to <math> \textdollar 2 </math>, <math> \textdollar 5 </math>, and <math> \textdollar 10 </math>, which | + | The three prices round to <math> \textdollar 2 </math>, <math> \textdollar 5 </math>, and <math> \textdollar 10 </math>, which have a sum of <math> \boxed{\textbf{(D)}\ 17} </math>. |
| + | We know that there will not be a rounding error, as the total amount rounded is clearly less than <math> \textdollar 0.50 </math>. | ||
| − | + | ==Video Solution by WhyMath== | |
| + | https://youtu.be/ZVg9Rva8ZIg | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2006|before=First <br />Question|num-a=2}} | {{AMC8 box|year=2006|before=First <br />Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 13:18, 29 October 2024
Problem
Mindy made three purchases for 
dollars, 
dollars, and 
dollars. What was her total, to the nearest dollar?
Solution
The three prices round to 
, 
, and 
, which have a sum of 
.
We know that there will not be a rounding error, as the total amount rounded is clearly less than 
.
Video Solution by WhyMath
See Also
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
