Difference between revisions of "2019 AMC 12B Problems/Problem 1"

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==Problem==
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==Solution==
 
==Solution==
  
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--mguempel
 
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==See Also==
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{{AMC12 box|year=2019|ab=B|num-b=12|num-a=14}}

Revision as of 11:18, 14 February 2019

Problem

Solution

Let the first jar's volume be $A$ and the second's be $B$. It is given that $\frac{3}{4}A=\frac{5}{6}B$. We find that $\frac{B}{A}=\frac{3/4}{5/6}=\boxed{\frac{9}{10}}.$

We already know that this is the ratio of smaller to larger volume because it is less than $1.$

--mguempel

See Also

2019 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions