Difference between revisions of "2018 UNM-PNM Statewide High School Mathematics Contest II Problems/Problem 4"
(→Solution) |
(→"90") |
||
Line 15: | Line 15: | ||
so Perimeter is 2(13+32)=90 | so Perimeter is 2(13+32)=90 | ||
− | =="90"== | + | ==""90""== |
== See also == | == See also == |
Revision as of 01:25, 8 August 2019
Contents
Problem
Suppose ABCD is a parallelogram with area square units and is a right angle. If the lengths of all the sides of ABCD are integers, what is the perimeter of ABCD?
Solution
Let any one side be x and other side be y.
Then one diagonal is [(y)^2-(x)^2]^(1/2)
let [(y)^2-(x)^2]^(1/2) be z. So x*z=39*95^(1/2)
Here x = 13 satisfies with y = 32 so Perimeter is 2(13+32)=90
""90""
See also
2018 UNM-PNM Contest II (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
All UNM-PNM Problems and Solutions |