Difference between revisions of "2004 AMC 12A Problems/Problem 9"
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To keep the volume the same, the height must be <math>\frac{1}{\frac{25}{16}}=\frac{16}{25}</math> of the original height, which is a <math>36\%</math> reduction <math>\Rightarrow\mathrm{(C)}</math>. | To keep the volume the same, the height must be <math>\frac{1}{\frac{25}{16}}=\frac{16}{25}</math> of the original height, which is a <math>36\%</math> reduction <math>\Rightarrow\mathrm{(C)}</math>. | ||
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[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
Revision as of 01:40, 11 September 2007
Problem
A company sells peanut butter in cylindrical jars. Marketing research suggests that using wider jars will increase sales. If the diameter of the jars is increased by 
without altering the volume, by what percent must the height be decreased?
Solution
When the diameter is increased by , is is increased by 
, so the area of the base is increased by 
.
To keep the volume the same, the height must be 
of the original height, which is a 
reduction 
.
See also
| 2004 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
