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Difference between revisions of "2002 AIME I Problems/Problem 10"
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== Problem ==
 
== Problem ==
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In the diagram below, angle <math>ABC</math> is a right angle. Point <math>D</math> is on <math>\overline{BC}</math>, and <math>\overline{AD}</math> bisects angle <math>CAB</math>. Points <math>E</math> and <math>F</math> are on <math>\overline{AB} and </math>\overline{AC}<math>, respectively, so that </math>AE=3<math> and </math>AF=10<math>. Given that </math>EB=9<math> and </math>FC=27<math>, find the integer closest to the area of quadrilateral </math>DCFG$.
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== Solution ==
 
== Solution ==

Revision as of 16:07, 25 September 2007

Problem

In the diagram below, angle $ABC$ is a right angle. Point $D$ is on $\overline{BC}$, and $\overline{AD}$ bisects angle $CAB$. Points $E$ and $F$ are on $\overline{AB} and$\overline{AC}$, respectively, so that$AE=3$and$AF=10$. Given that$EB=9$and$FC=27$, find the integer closest to the area of quadrilateral$DCFG$.

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Solution

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See also

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