Difference between revisions of "2020 USOMO Problems"

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An empty <math>2020 \times 2020 \times 2020</math> cube is given, and a <math>2020 \times 2020</math> grid of square unit cells is drawn on each of its six faces. A beam is a <math>1 \times 1 \times 2020</math> rectangular prism. Several beams are placed inside the cube subject to the following conditions:
 
An empty <math>2020 \times 2020 \times 2020</math> cube is given, and a <math>2020 \times 2020</math> grid of square unit cells is drawn on each of its six faces. A beam is a <math>1 \times 1 \times 2020</math> rectangular prism. Several beams are placed inside the cube subject to the following conditions:
  
<math>\bullet</math> The two <math>1 \times 1</math> faces of each beam coincide with unit cells lying on opposite faces
+
<math>\bullet</math> The two <math>1 \times 1</math> faces of each beam coincide with unit cells lying on opposite faces of the cube. (Hence, there are <math>3 \cdot 2020^2</math> possible positions for a beam.)
of the cube. (Hence, there are <math>3 \cdot 2020^2</math> possible positions for a beam.)
+
 
 
<math>\bullet</math> No two beams have intersecting interiors.
 
<math>\bullet</math> No two beams have intersecting interiors.
<math>\bullet</math> The interiors of each of the four <math>1 \times 2020</math> faces of each beam touch either a face of the cube or the interior of the face of another beam.
+
 
 +
<math>\bullet</math> The interiors of each of the four <math>1 \times 2020</math> faces of each beam touch either a face
 +
of the cube or the interior of the face of another beam.
  
 
What is the smallest positive number of beams that can be placed to satisfy these conditions?
 
What is the smallest positive number of beams that can be placed to satisfy these conditions?
 
  
 
[[2020 USOMO Problems/Problem 2|Solution]]
 
[[2020 USOMO Problems/Problem 2|Solution]]
  
 
===Problem 3===
 
===Problem 3===
Let <math>p</math> be an odd prime. An integer <math>x</math> is called a <i>quadratic non-residue</i> if
+
Let <math>p</math> be an odd prime. An integer <math>x</math> is called a <i>quadratic non-residue</i> if <math>p</math> does not divide <math>x - t^2</math> for any integer <math>t</math>.
<math>p</math> does not divide <math>x - t^2</math> for any integer <math>t</math>.
 
  
Denote by <math>A</math> the set of all integers <math>a</math> such that <math>1 \le a < p</math>, and both <math>a</math> and <math>4 - a</math> are
+
Denote by <math>A</math> the set of all integers <math>a</math> such that <math>1 \le a < p</math>, and both <math>a</math> and <math>4 - a</math> are quadratic non-residues. Calculate the remainder when the product of the elements of <math>A</math> is divided by <math>p</math>.
quadratic non-residues. Calculate the remainder when the product of the elements of <math>A</math>
 
is divided by <math>p</math>.
 
  
 
[[2020 USOMO Problems/Problem 3|Solution]]
 
[[2020 USOMO Problems/Problem 3|Solution]]
  
 
==Day 2==
 
==Day 2==

Revision as of 01:05, 23 June 2020

Day 1

Problem 1

Let $ABC$ be a fixed acute triangle inscribed in a circle $\omega$ with center $O$. A variable point $X$ is chosen on minor arc $AB$ of $\omega$, and segments $CX$ and $AB$ meet at $D$. Denote by $O_1$ and $O_2$ the circumcenters of triangles $ADX$ and $BDX$, respectively. Determine all points $X$ for which the area of triangle $OO_1O_2$ is minimized.

Solution

Problem 2

An empty $2020 \times 2020 \times 2020$ cube is given, and a $2020 \times 2020$ grid of square unit cells is drawn on each of its six faces. A beam is a $1 \times 1 \times 2020$ rectangular prism. Several beams are placed inside the cube subject to the following conditions:

$\bullet$ The two $1 \times 1$ faces of each beam coincide with unit cells lying on opposite faces of the cube. (Hence, there are $3 \cdot 2020^2$ possible positions for a beam.)

$\bullet$ No two beams have intersecting interiors.

$\bullet$ The interiors of each of the four $1 \times 2020$ faces of each beam touch either a face of the cube or the interior of the face of another beam.

What is the smallest positive number of beams that can be placed to satisfy these conditions?

Solution

Problem 3

Let $p$ be an odd prime. An integer $x$ is called a quadratic non-residue if $p$ does not divide $x - t^2$ for any integer $t$.

Denote by $A$ the set of all integers $a$ such that $1 \le a < p$, and both $a$ and $4 - a$ are quadratic non-residues. Calculate the remainder when the product of the elements of $A$ is divided by $p$.

Solution

Day 2