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Difference between revisions of "2021 AMC 10A Problems/Problem 1"

(Created page with "== Problem == What is the value of <cmath>(2^2-2)-(3^2-3)+(4^2-4)</cmath> <math>\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textb...")
 
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<math>\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12</math>
 
<math>\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12</math>
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== Solution ==
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<math>(4-2)-(9-3)+(16-4)=2-6+12=8. This corresponds to \boxed{\text{D}}</math>
 +
-happykeeper

Revision as of 13:19, 11 February 2021

Problem

What is the value of \[(2^2-2)-(3^2-3)+(4^2-4)\]

$\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12$

Solution

$(4-2)-(9-3)+(16-4)=2-6+12=8. This corresponds to \boxed{\text{D}}$ -happykeeper

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