Difference between revisions of "Midpoint"

Revision as of 10:02, 12 February 2021

Definition

The midpoint of a line segment is the point on the segment equidistant from both endpoints.

A midpoint bisects the line segment that the midpoint lies on. Because of this property, we say that for any line segment $\overline{AB}$ with midpoint $M$ , $AM=BM=\frac{1}{2}AB$ . Alternatively, any point $M$ on $\overline{AB}$ such that $AM=BM$ is the midpoint of the segment. $[asy] draw((0,0)--(4,0)); dot((0,0)); label("A",(0,0),N); dot((4,0)); label("B",(4,0),N); dot((2,0)); label("M",(2,0),N); label("Figure 1",(2,0),4S); [/asy]$

Midpoints and Triangles

$[asy] pair A,B,C,D,E,F,G; A=(0,0); B=(4,0); C=(1,3); D=(2,0); E=(2.5,1.5); F=(0.5,1.5); G=(5/3,1); draw(A--B--C--cycle); draw(D--E--F--cycle,green); dot(A--B--C--D--E--F--G); draw(A--E,red); draw(B--F,red); draw(C--D,red); label("A",A,S); label("B",B,S); label("C",C,N); label("D",D,S); label("E",E,E); label("F",F,W); label("G",G,NE); label("Figure 2",D,4S); [/asy]$

Midsegments

As shown in Figure 2, $\Delta ABC$ is a triangle with $D$ , $E$ , $F$ midpoints on $\overline{AB}$ , $\overline{BC}$ , $\overline{CA}$ respectively. Connect $\overline{EF}$ , $\overline{FD}$ , $\overline{DE}$ (segments highlighted in green). They are midsegments to their corresponding sides. Using SAS Similarity Postulate, we can see that $\Delta CFE \sim \Delta CAB$ and likewise for $\Delta ADF$ and $\Delta BED$ . Because of this, we know that $\begin{align*} AB &= 2FE \\ BC &= 2DE \\ CA &= 2ED \\ \end{align*}$ Which is the Triangle Midsegment Theorem. Because we have a relationship between these segment lengths, $\Delta ABC \sim \Delta EFD (SSS)$ with similar ratio 2:1. The area ratio is then 4:1; this tells us $\begin{align*} [ABC] &= 4[EFD] \end{align*}$

Cartesian Plane

In the Cartesian Plane, the coordinates of the midpoint $M$ can be obtained when the two endpoints $A$ , $B$ of the line segment $\overline{AB}$ is known. Say that $A: A(x_A,y_A)$ and $B: B(x_B,y_B)$ . The Midpoint Formula states that the coordinates of $M$ can be calculated as: $\begin{align*} M(\frac{x_A+x_B}{2}&,\frac{y_A+y_B}{2}) \end{align*}$

@@ Line 45: / Line 45: @@
 CA &= 2ED \\
 \end{align*}</cmath>
-Which is the Triangle Midsegment Theorem. Because we have a relationship between these segment lengths, <math>\Delta ABC \sim \Delta EFD (SSS)</math> with similar ratio 2:1. The area ratio is then 4:1; this tells us
+Which is the Triangle Midsegment Theorem. Because we have a relationship between these segment lengths, <math>\Delta ABC \sim \Delta EFD  (SSS)</math> with similar ratio 2:1. The area ratio is then 4:1; this tells us
 <cmath>\begin{align*}
 [ABC] &= 4[EFD]
 \end{align*}</cmath>
 == Cartesian Plane ==
 In the Cartesian Plane, the coordinates of the midpoint <math>M</math> can be obtained when the two endpoints <math>A</math>, <math>B</math> of the line segment <math>\overline{AB}</math> is known. Say that <math>A: A(x_A,y_A)</math> and <math>B: B(x_B,y_B)</math>. The Midpoint Formula states that the coordinates of <math>M</math> can be calculated as:

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