Difference between revisions of "Euclid 2018"
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Therefore one piece of chocolate bar is 1 + 1.05 = <math>\boxed{2.05}</math> | Therefore one piece of chocolate bar is 1 + 1.05 = <math>\boxed{2.05}</math> | ||
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| + | ~ North America Math Contest Go Go Go | ||
== Video Solution == | == Video Solution == | ||
Latest revision as of 14:44, 11 April 2021
Problem
a) Given x = 11, find (x) + (x+1) + (x+2) + (x+3)
b) Given 
+ 
= 1, find the value of a
c) The total cost of one chocolate bar and two identical packs of gums is 4.15 dollars. One chocolate bar costs 1 dollar more than one pack of gum. Find the price of a chocolate bar.
Solution
a) Plug x = 11 back to the original equation
(11) + (11+1) + (11+2) + (11+3) = 
b)By simplifcation:
+
= 1
+ = 1
= 1
Therefore a = 
c) Set One chocolate bar as x + 1 and one piece of gum as x dollars. We get:
Therefore one piece of chocolate bar is 1 + 1.05 = 
~ North America Math Contest Go Go Go
