Difference between revisions of "1956 AHSME Problems/Problem 20"
Angrybird029 (talk | contribs) (Created page with "If <math>(0.2)^x = 2</math> and <math>\log 2 = 0.3010</math>, then the value of <math>x</math> to the nearest tenth is: <math>\textbf{(A)}\ - 10.0 \qquad\textbf{(B)}\ - 0.5 \...") |
Angrybird029 (talk | contribs) (→Solution) |
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<math>\textbf{(A)}\ - 10.0 \qquad\textbf{(B)}\ - 0.5 \qquad\textbf{(C)}\ - 0.4 \qquad\textbf{(D)}\ - 0.2 \qquad\textbf{(E)}\ 10.0</math> | <math>\textbf{(A)}\ - 10.0 \qquad\textbf{(B)}\ - 0.5 \qquad\textbf{(C)}\ - 0.4 \qquad\textbf{(D)}\ - 0.2 \qquad\textbf{(E)}\ 10.0</math> | ||
==Solution== | ==Solution== | ||
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Latest revision as of 16:39, 21 June 2021
If and
, then the value of
to the nearest tenth is:
Solution
To be added.