Difference between revisions of "2021 JMPSC Sprint Problems/Problem 12"
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Note that <math>\sqrt{x}=x^{\frac{1}{2}}</math>. So <math>{x}\sqrt{x^{\frac{3}{2}}}=2^{63}</math>. Simplifying gives that <math>x{\cdot}x^{\frac{3}{4}}=x^{\frac{7}{4}}=2^{63}</math>. If <math>x</math> is <math>2^m</math>, then <math>\frac{7m}{4}=63</math>, so <math>m=\boxed{36}</math>. | Note that <math>\sqrt{x}=x^{\frac{1}{2}}</math>. So <math>{x}\sqrt{x^{\frac{3}{2}}}=2^{63}</math>. Simplifying gives that <math>x{\cdot}x^{\frac{3}{4}}=x^{\frac{7}{4}}=2^{63}</math>. If <math>x</math> is <math>2^m</math>, then <math>\frac{7m}{4}=63</math>, so <math>m=\boxed{36}</math>. | ||
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+ | ==Solution 3== | ||
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+ | We square both sides of the equation to get <cmath>x^2 \cdot x\sqrt{x}=x^2\sqrt{x}=2^{63 \cdot 2}.</cmath> We square both sides of the equation again to get <cmath>x^6 \cdot x=x^7=2^{63 \cdot 4}.</cmath> Thus, <math>x=2^{63 \cdot 4/7}=2^{36}</math>, so the answer is <math>\boxed{36}</math>. |
Revision as of 11:51, 11 July 2021
Contents
Problem
The solution to the equation can be written as , where is a real number. What is ?
Solution
Let Then, we have that the expression on the left hand side is equivalent to Thus, we have that Taking the 7th root of both sides gives thus we have which makes Answer is
~Lamboreghini
Solution 2
Note that . So . Simplifying gives that . If is , then , so .
Solution 3
We square both sides of the equation to get We square both sides of the equation again to get Thus, , so the answer is .