Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 7"
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− | Notice that <math>C</math> can only be <math>0</math> and <math>5</math>. However, <math>790</math> is not divisible by <math>3</math>, so | + | Notice that <math>C</math> can only be <math>0</math> and <math>5</math>. However, <math>790</math> is not divisible by <math>3</math>, so <cmath>3 \times ABC = 795</cmath> <cmath>ABC = 265</cmath> Thus, <math>3A + 2B + C = \boxed{23}</math> |
~Bradygho | ~Bradygho |
Revision as of 14:18, 11 July 2021
Problem
If ,
, and
each represent a single digit and they satisfy the equation
find
.
Solution
Notice that can only be
and
. However,
is not divisible by
, so
Thus,
~Bradygho
Solution 2
Clearly we see does not work, but
works with simple guess-and-check. We have
, so
and
. The answer is
~Geometry285