Difference between revisions of "User:Temperal/Introductory Proportion"
| Line 9: | Line 9: | ||
==Solution== | ==Solution== | ||
{{incomplete|solution}} | {{incomplete|solution}} | ||
| − | If <math>x=\frac{1} {20}</math>, then <math> \frac{y} {20} = \frac{1} {k}</math> so <math>ky=20</math> or <math>ky=\frac{1} {20}</math>. | + | If <math>x=\frac{1} {20}</math>, then <math> \frac{y} {20} = \frac{1} {k}</math> so <math>ky=20</math> or <math>ky=\frac{1} {20}</math>. now we get <math>k=\frac{20} {y}</math> and <math>\frac{1} {20y}</math> |
Revision as of 12:27, 22 September 2007
Problem
Suppose 
is either x or y in the following system:
![\[\begin{cases} xy=\frac{1}{k}\\ x=ky \end{cases}\]](http://latex.artofproblemsolving.com/4/8/f/48f37af559f7c66fe3ccb3fb9b0e6c16b3fec444.png)
Find the possible values of k.
Solution
Template:Incomplete
If 
, then 
so 
or 
. now we get 
and 
