Difference between revisions of "Multinomial Theorem"

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is simplified by expanding it and combining like terms. How many terms are in the simplified expression?
 
is simplified by expanding it and combining like terms. How many terms are in the simplified expression?
  
<math> \mathrm{(A) \ } 6018\qquad \mathrm{(B) \ } 671,676\qquad \mathrm{(C) \ } 1,007,514</math><math>\mathrm{(D) \ } 1,008,016\qquad\mathrm{(E) \ }  2,015,028</math>
+
<math> \mathrm{(A) \ } 6018\qquad \mathrm{(B) \ } 671,676\qquad \mathrm{(C) \ } 1,007,514\qquad \mathrm{(D) \ } 1,008,016\qquad\mathrm{(E) \ }  2,015,028</math>
  
 
-([[2006_AMC_12A_Problems/Problem_24|2006 AMC 12A Problem 24]])
 
-([[2006_AMC_12A_Problems/Problem_24|2006 AMC 12A Problem 24]])
 +
 
===Olympiad===
 
===Olympiad===
  

Revision as of 10:12, 29 April 2008

The multinomial theorem states that

$(a_1+a_2+\cdots+a_x)^n=\sum_{k_1,k_2,\cdots,k_x}\binom{n}{k_1,k_2,\cdots,k_x}a_1^{k_1}a_2^{k_2}\cdots a_x^{k_x}$

where

$\binom{n}{k_1,k_2,\cdots,k_x}=\dfrac{n!}{k_1!k_2!\cdots k_x!}$

Problems

Introductory

Intermediate

  • The expression

$(x+y+z)^{2006}+(x-y-z)^{2006}$

is simplified by expanding it and combining like terms. How many terms are in the simplified expression?

$\mathrm{(A) \ } 6018\qquad \mathrm{(B) \ } 671,676\qquad \mathrm{(C) \ } 1,007,514\qquad \mathrm{(D) \ } 1,008,016\qquad\mathrm{(E) \ }  2,015,028$

-(2006 AMC 12A Problem 24)

Olympiad

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