Difference between revisions of "1985 AJHSME Problem 9"
(→In-depth Solution by Boundless Brain!) |
(→Solution) |
||
| Line 11: | Line 11: | ||
<cmath>\frac{1}{2} \cdot \frac{2}{3} \dots \frac{9}{10}.</cmath> | <cmath>\frac{1}{2} \cdot \frac{2}{3} \dots \frac{9}{10}.</cmath> | ||
Numerators and denominators cancel to yield the answer: <math>\boxed{\text{(A)} \frac{1}{10}}.</math> | Numerators and denominators cancel to yield the answer: <math>\boxed{\text{(A)} \frac{1}{10}}.</math> | ||
| + | |||
| + | == Solution 2 (Brute Force) == | ||
Revision as of 07:26, 6 October 2024
Problem
The product of the 9 factors 
In-depth Solution by BoundlessBrain!
Solution
This product simplifies to:
![\[\frac{1}{2} \cdot \frac{2}{3} \dots \frac{9}{10}.\]](http://latex.artofproblemsolving.com/c/d/f/cdf3e4229337b6e0cb5e4e4d010c70f59ef5a685.png)
Numerators and denominators cancel to yield the answer: 
