Difference between revisions of "2023 AMC 10B Problems/Problem 20"
E is 2.71828 (talk | contribs) m (→Problem 20) |
E is 2.71828 (talk | contribs) (→Problem 20) |
||
Line 3: | Line 3: | ||
shown, creating a close curve that divides the surface into two congruent regions. | shown, creating a close curve that divides the surface into two congruent regions. | ||
The length of the curve is <math>\pi\sqrt{n}</math>. What is 𝑛? | The length of the curve is <math>\pi\sqrt{n}</math>. What is 𝑛? | ||
+ | |||
+ | <math>\textbf{(A) } 32 \qquad \textbf{(B) } 12 \qquad \textbf{(C) } 48 \qquad \textbf{(D) } 36 \qquad \textbf{(E) } 27</math> | ||
[[Image:202310bQ20.jpeg]] | [[Image:202310bQ20.jpeg]] |
Revision as of 18:37, 15 November 2023
Problem 20
Four congruent semicircles are drawn on the surface of a sphere with radius 2, as shown, creating a close curve that divides the surface into two congruent regions. The length of the curve is . What is 𝑛?
Solution 1
There are four marked points on the diagram; let us examine the top two points and call them and . Similarly, let the bottom two dots be and , as shown:
This is a cross-section of the sphere seen from the side. We know that , and by Pythagorean therorem,
Each of the four congruent semicircles has the length as a diameter (since is congruent to and ), so its radius is Each one's arc length is thus
We have of these, so the total length is , so thus our answer is
~Technodoggo
Solution 2
Assume , , , and are the four points connecting the semicircles. By law of symmetry, we can pretty confidently assume that is a square. Then, , and the rest is the same as the second half of solution .
~jonathanzhou18
Solution 3
We put the sphere to a coordinate space by putting the center at the origin. The four connecting points of the curve have the following coordinates: , , , .
Now, we compute the radius of each semicircle. Denote by the midpoint of and . Thus, is the center of the semicircle that ends at and . We have . Thus, .
In the right triangle , we have .
Therefore, the length of the curve is
Therefore, the answer is .
~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com)
Solution 4
Note that each of the diameters are the chord of the sphere of a quarter arc. Thus, the semicircles diameter's length is . Thus, the entire curve is . Therefore, the answer is .