Difference between revisions of "1987 OIM Problems/Problem 6"

(Created page with "== Problem == Let <math>ABCD</math> be a planar convex quadrilateral, <math>P</math> and <math>QQ</math> are points of <math>AD</math> and <math>BC</math> respectively such th...")
 
 
Line 3: Line 3:
 
<cmath>\frac{AP}{PD}=\frac{AB}{DC}=\frac{BQ}{QC}</cmath>
 
<cmath>\frac{AP}{PD}=\frac{AB}{DC}=\frac{BQ}{QC}</cmath>
 
Prove that the angles that are formed between line <math>PQ</math> and lines <math>AB</math> and <math>DC</math> are equal.
 
Prove that the angles that are formed between line <math>PQ</math> and lines <math>AB</math> and <math>DC</math> are equal.
 +
 +
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
  
 
== Solution ==
 
== Solution ==
 
{{solution}}
 
{{solution}}
 +
 +
== See also ==
 +
https://www.oma.org.ar/enunciados/ibe2.htm

Latest revision as of 12:27, 13 December 2023

Problem

Let $ABCD$ be a planar convex quadrilateral, $P$ and $QQ$ are points of $AD$ and $BC$ respectively such that: \[\frac{AP}{PD}=\frac{AB}{DC}=\frac{BQ}{QC}\] Prove that the angles that are formed between line $PQ$ and lines $AB$ and $DC$ are equal.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See also

https://www.oma.org.ar/enunciados/ibe2.htm