Difference between revisions of "1988 OIM Problems/Problem 2"

(Problem)
 
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(ii) If <math>q=b+d</math>, then <math>p=a+c</math>.
 
(ii) If <math>q=b+d</math>, then <math>p=a+c</math>.
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 +
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
  
 
== Solution ==
 
== Solution ==
 
{{solution}}
 
{{solution}}
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== See also ==
 +
https://www.oma.org.ar/enunciados/ibe3.htm

Latest revision as of 12:28, 13 December 2023

Problem

Let $a$, $b$, $c$, $d$, $p$, and $q$, be non-zero natural numbers that verify $ad-bc=1$, and $\frac{a}{b} >\frac{p}{q}>\frac{c}{d}$.

Prove:

(i) $q \ge b+d$

(ii) If $q=b+d$, then $p=a+c$.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See also

https://www.oma.org.ar/enunciados/ibe3.htm