Difference between revisions of "2002 AMC 12P Problems/Problem 6"
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== Problem == | == Problem == | ||
− | + | Participation in the local soccer league this year is <math>10</math>% higher than last year. The number of males increased by <math>5</math>% and the number of females increased by <math>20</math>%. What fraction of the soccer league is now female? | |
− | <math> \ | + | <math> |
+ | \text{(A) }\frac{1}{3} | ||
+ | \qquad | ||
+ | \text{(B) }\frac{4}{11} | ||
+ | \qquad | ||
+ | \text{(C) }\frac{2}{5} | ||
+ | \qquad | ||
+ | \text{(D) }\frac{4}{9} | ||
+ | \qquad | ||
+ | \text{(E) }\frac{1}{2} | ||
+ | </math> | ||
== Solution == | == Solution == |
Revision as of 23:44, 29 December 2023
Problem
Participation in the local soccer league this year is % higher than last year. The number of males increased by % and the number of females increased by %. What fraction of the soccer league is now female?
Solution
If , then . Since , must be to some factor of 6. Thus, there are four (3, 9, 27, 729) possible values of .
See also
2002 AMC 12P (Problems • Answer Key • Resources) | |
Preceded by Problem 5 |
Followed by Problem 7 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.