Difference between revisions of "2005 Alabama ARML TST Problems/Problem 8"

(New page: ==Problem== How many of the positive divisors of 3,240,000 are perfect cubes? ==Solution== {{solution}} ==See Also== *2005 Alabama ARML TST *[[2005 Alabama ARML TST Probl...)
 
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==Problem==
 
==Problem==
How many of the [[positive]] [[divisor]]s of 3,240,000 are [[perfect cube]]s?
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Find the number of ordered pairs of integers <math>(x,y)</math> which satisfy <center><math>x^2+4xy+y^2=21</math>.</center>
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==Solution==
 
==Solution==
  
 
{{solution}}
 
{{solution}}
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==See Also==
 
==See Also==

Revision as of 10:42, 10 December 2007

Problem

Find the number of ordered pairs of integers $(x,y)$ which satisfy

$x^2+4xy+y^2=21$.

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.


See Also