Difference between revisions of "2024 AIME II Problems/Problem 15"
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Problem: Suppose we have <math>69</math> chicken eggs and <math>696</math> egg eggs. Find the square root of the total number of true eggs that are 69able. | Problem: Suppose we have <math>69</math> chicken eggs and <math>696</math> egg eggs. Find the square root of the total number of true eggs that are 69able. | ||
− | Solution: Using the <cmath>Egger's Eg(g)regious Eggo Eggnog Egg law</cmath>, we can use the <math>Monkey Math Law</math> to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields <math>\boxed{264}</math>. | + | Solution: |
+ | Using the <cmath>Egger's Eg(g)regious Eggo Eggnog Egg law</cmath>, we can use the <math>Monkey Math Law</math> to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields <math>\boxed{264}</math>. |
Revision as of 00:38, 24 January 2024
Problem: Suppose we have chicken eggs and egg eggs. Find the square root of the total number of true eggs that are 69able.
Solution: Using the , we can use the to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields .