Difference between revisions of "2024 AIME II Problems/Problem 15"

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Problem: Suppose we have <math>69</math> chicken eggs and <math>696</math> egg eggs. Find the square root of the total number of true eggs that are 69able.
 
Problem: Suppose we have <math>69</math> chicken eggs and <math>696</math> egg eggs. Find the square root of the total number of true eggs that are 69able.
  
Solution: Using the <cmath>Egger's Eg(g)regious Eggo Eggnog Egg law</cmath>, we can use the <math>Monkey Math Law</math> to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields <math>\boxed{264}</math>.
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Solution:
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Using the <cmath>Egger's Eg(g)regious Eggo Eggnog Egg law</cmath>, we can use the <math>Monkey Math Law</math> to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields <math>\boxed{264}</math>.

Revision as of 00:38, 24 January 2024

Problem: Suppose we have $69$ chicken eggs and $696$ egg eggs. Find the square root of the total number of true eggs that are 69able.

Solution: Using the \[Egger's Eg(g)regious Eggo Eggnog Egg law\], we can use the $Monkey Math Law$ to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields $\boxed{264}$.