Difference between revisions of "2024 AMC 8 Problems/Problem 1"
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<math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math> | <math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math> | ||
− | ==Solution | + | ==Solution 2== |
We can rewrite the expression as <cmath>222,222-(22,222+2,222+222+22+2)</cmath>. | We can rewrite the expression as <cmath>222,222-(22,222+2,222+222+22+2)</cmath>. | ||
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~ Dreamer1297 | ~ Dreamer1297 | ||
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==Solution 2== | ==Solution 2== |
Revision as of 15:17, 25 January 2024
Problem
What is the ones digit of
Solution 2
We can rewrite the expression as .
We note that the units digit of the addition is because all the units digits of the five numbers are and , which has a units digit of .
Now, we have something with a units digit of subtracted from . The units digit of this expression is obviously , and we get as our answer.
~ Dreamer1297
Solution 2
This means the ones digit is ~ nikhil ~ CXP