Difference between revisions of "2024 AMC 8 Problems/Problem 2"
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4+2.5+0.04 reveals <cmath>\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}</cmath> is <math>\boxed{\textbf{(C)\ 6.54}}</math>. | 4+2.5+0.04 reveals <cmath>\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}</cmath> is <math>\boxed{\textbf{(C)\ 6.54}}</math>. | ||
~ le_petit_chouetteur from TSMV | ~ le_petit_chouetteur from TSMV | ||
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| + | ==Video Solution 1 (Quick and Easy!)== | ||
| + | https://youtu.be/nzPT89ymlKk | ||
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| + | ~Education, the Study of Everything | ||
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==Video Solution by Math-X (First understand the problem!!!)== | ==Video Solution by Math-X (First understand the problem!!!)== | ||
Revision as of 01:15, 3 March 2024
Contents
Problem 2
What is the value of this expression in decimal form?
![\[\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}\]](http://latex.artofproblemsolving.com/5/c/7/5c7e5b58fa8556742330357616baa41f8daabd7a.png)
Solution 1
We see that 44/11 is 4; 110/44 simplifies to 5/2, which is 2.5;
and 44/1100 simplifies to 1/25, which is 0.04;
4+2.5+0.04 reveals is 
.
~ le_petit_chouetteur from TSMV
Video Solution 1 (Quick and Easy!)
~Education, the Study of Everything
Video Solution by Math-X (First understand the problem!!!)
https://youtu.be/BaE00H2SHQM?si=noTBPTosCtH31CpW&t=287
~Math-X
See Also
| 2024 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
