Difference between revisions of "ASIA TEAM Problems/Problem 2"

Latest revision as of 05:13, 16 February 2024

Notice that $...S_4S_3S_2S_1$ is the base-4 representation of $2013$ , and $2013_{10}=133131$ , so the answer is $1+3+3+1+3+1=\boxed{12}$ . ~AbbyWong

Revision as of 05:12, 16 February 2024 (view source) Abbywong (talk \| contribs) (Created page with "Notice that <math>...S_4S_3S_2S_1</math> is the base-4 representation of <math>2013</math>, and <math>2013_{10}=</math>133131<math>, so the answer is </math>1+3+3+1+3+1=\boxed...")		Latest revision as of 05:13, 16 February 2024 (view source) Abbywong (talk \| contribs)
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−	Notice that <math>...S_4S_3S_2S_1</math> is the base-4 representation of <math>2013</math>, and <math>2013_{10}=</~~math>133131<~~math>, so the answer is </math>1+3+3+1+3+1=\boxed{12}$.	+	Notice that <math>...S_4S_3S_2S_1</math> is the base-4 representation of <math>2013</math>, and <math>2013_{10}=133131</math>, so the answer is <math>1+3+3+1+3+1=\boxed{12}</math>.
	~AbbyWong		~AbbyWong