Difference between revisions of "2024 AMC 10A Problems/Problem 2"
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<math>\textbf{(A) } \text{R E D} \qquad\textbf{(B) } \text{L S T E R} \qquad\textbf{(C) } \text{Q E D} \qquad\textbf{(D) } \text{L M N O P} \qquad\textbf{(E) } 42 </math> | <math>\textbf{(A) } \text{R E D} \qquad\textbf{(B) } \text{L S T E R} \qquad\textbf{(C) } \text{Q E D} \qquad\textbf{(D) } \text{L M N O P} \qquad\textbf{(E) } 42 </math> | ||
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| + | ==Brute Force(common sense)== | ||
| + | The e and r are right so flip it and you’re only missing the d but by alphabetical order d=4 s=19 t=20 l=12 20/19=1(rounded), +19=20 lster is 5 letters so divide it by 5, 20/5=4(d) and the l is irrelevant. So its <math>\textbf{(B)}</math> | ||
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==Video Solution== | ==Video Solution== | ||
https://youtu.be/sHQgxWPJSKc?si=bTNk8EXGJw5pThy7 | https://youtu.be/sHQgxWPJSKc?si=bTNk8EXGJw5pThy7 | ||
Revision as of 19:08, 9 August 2024
Spell "red"
Brute Force(common sense)
The e and r are right so flip it and you’re only missing the d but by alphabetical order d=4 s=19 t=20 l=12 20/19=1(rounded), +19=20 lster is 5 letters so divide it by 5, 20/5=4(d) and the l is irrelevant. So its 
