Difference between revisions of "2024 AMC 10B Problems/Problem 6"
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Solution by [[User:IshikaSaini|IshikaSaini]]. | Solution by [[User:IshikaSaini|IshikaSaini]]. | ||
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| + | ==Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)== | ||
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| + | https://youtu.be/QLziG_2e7CY?feature=shared | ||
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| + | ~ Pi Academy | ||
==See also== | ==See also== | ||
{{AMC10 box|year=2024|ab=B|num-b=5|num-a=7}} | {{AMC10 box|year=2024|ab=B|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 10:00, 14 November 2024
Contents
Problem
A rectangle has integer length sides and an area of 2024. What is the least possible perimeter of the rectangle?
Solution 1 - Prime Factorization
We can start by assigning the values x and y for both sides. Here is the equation representing the area:
Let's write out 2024 fully factorized.
Since we know that 
, we want the two closest numbers possible. After some quick analysis, those two numbers are 
and 
. 
Now we multiply by 
and get 
Solution by IshikaSaini.
Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)
https://youtu.be/QLziG_2e7CY?feature=shared
~ Pi Academy
See also
| 2024 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
