Difference between revisions of "1987 AJHSME Problems/Problem 1"

(New page: ==Problem== <math>.4+.02+.006=</math> <math>\text{(A)}\ .012 \qquad \text{(B)}\ .066 \qquad \text{(C)}\ .12 \qquad \text{(D)}\ .24 \qquad \text{(E)} .426</math> ==Solution== {{Solution...)
 
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==Solution==
 
==Solution==
  
{{Solution}}
+
<math>.4+.02+.006 = .400 + .020 + .006 = \boxed{.426}</math>
  
 
==See Also==
 
==See Also==
  
 
[[1987 AJHSME Problems]]
 
[[1987 AJHSME Problems]]

Revision as of 13:50, 29 January 2009

Problem

$.4+.02+.006=$

$\text{(A)}\ .012 \qquad \text{(B)}\ .066 \qquad \text{(C)}\ .12 \qquad \text{(D)}\ .24 \qquad \text{(E)} .426$

Solution

$.4+.02+.006 = .400 + .020 + .006 = \boxed{.426}$

See Also

1987 AJHSME Problems