Difference between revisions of "1987 AJHSME Problems/Problem 14"

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==See Also==
 
==See Also==
  
[[1987 AJHSME Problems]]
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{{AJHSME box|year=1987|num-b=13|num-a=15}}
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[[Category:Introductory Algebra Problems]]

Revision as of 15:11, 29 May 2009

Problem

A computer can do $10,000$ additions per second. How many additions can it do in one hour?

$\text{(A)}\ 6\text{ million} \qquad \text{(B)}\ 36\text{ million} \qquad \text{(C)}\ 60\text{ million} \qquad \text{(D)}\ 216\text{ million} \qquad \text{(E)}\ 360\text{ million}$

Solution

There are $3600$ seconds per hour, so we have \begin{align*} \frac{3600\text{ seconds}}{\text{hour}}\cdot \frac{10,000\text{ additions}}{\text{second}} &= \frac{36,000,000\text{ additions}}{\text{hour}} \\ &= 36\text{ million additions per hour}  \end{align*}

$\boxed{\text{B}}$

See Also

1987 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
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All AJHSME/AMC 8 Problems and Solutions