Difference between revisions of "User:R31415"

Revision as of 20:04, 7 January 2011

$e^i*e^\pi=-1$ Which means that i^i equals (e^i*e^\pi*e^1/2)^i= e^-\pi/2

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	'''<math>e^i*e^\pi=-1</math>'''		'''<math>e^i*e^\pi=-1</math>'''
		+	Which means that i^i equals (e^ie^\pie^1/2)^i= e^-\pi/2