Difference between revisions of "2010 AMC 10B Problems/Problem 12"

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The minimum possible value occurs when 20% of the students who originally answered "No." answer "Yes." In this case, x=20
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The minimum possible value occurs when <math>20%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=20</math>
  
The maximum possible value occurs when 30% of the students who originally answered "Yes." answer "No." and the 50% of the students who originally answered "No." answer "Yes." In this case, x=50+30=80
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The maximum possible value occurs when <math>30%</math> of the students who originally answered "Yes." answer "No." and the <math>50%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=50+30=80</math>
  
Subtract 20 from 80 to obtain an answer of <math>\boxed{\mathrm {(D)} 60}</math>
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Subtract <math>80-20</math> to obtain an answer of <math>\boxed{\mathrm{(D)} 60}</math>

Revision as of 14:03, 24 January 2011

The minimum possible value occurs when $20%$ (Error compiling LaTeX. Unknown error_msg) of the students who originally answered "No." answer "Yes." In this case, $x=20$

The maximum possible value occurs when $30%$ (Error compiling LaTeX. Unknown error_msg) of the students who originally answered "Yes." answer "No." and the $50%$ (Error compiling LaTeX. Unknown error_msg) of the students who originally answered "No." answer "Yes." In this case, $x=50+30=80$

Subtract $80-20$ to obtain an answer of $\boxed{\mathrm{(D)} 60}$