Difference between revisions of "2004 AMC 10B Problems/Problem 24"
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== Solution == | == Solution == | ||
− | Set <math> BD </math>'s length as <math> x </math>. <math> CD </math>'s length must also be <math> x </math>. Using Ptolemy's Theorem, <math> 7x+8x=9(AD) </math>. The ratio is <math> \boxed{\frac{5}{3}}\implies(C) </math> | + | Set <math>\segment BD</math>'s length as <math>x</math>. <math>CD</math>'s length must also be <math>x</math> since <math> \angle BAD </math> and <math> \angle DAC </math> intercept arcs of equal length. Using [[Ptolemy's Theorem]], <math>7x+8x=9(AD)</math>. The ratio is <math>\boxed{\frac{5}{3}}\implies(C)</math> |
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+ | == See Also == | ||
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+ | {{AMC10 box|year=2004|ab=B|num-b=23|num-a=25}} |
Revision as of 15:57, 1 May 2011
In triangle we have , , . Point is on the circumscribed circle of the triangle so that bisects angle . What is the value of ?
Solution
Set $\segment BD$ (Error compiling LaTeX. Unknown error_msg)'s length as . 's length must also be since and intercept arcs of equal length. Using Ptolemy's Theorem, . The ratio is
See Also
2004 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |