Difference between revisions of "2012 AMC 10B Problems/Problem 13"

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== Solution ==
 
== Solution ==
  
The same distance is being covered in each of the three scenarios. Let s be the speed of the escalator and c be the speed of Clea. Using d = v t, the first statement can be translated to the equation d = 60c. The second statement can be translated to d = 24(c+s). Equating and solving for s we find: s = 3c/2. The problem asks for the time it takes her to ride down the escalator. Since t = d/s and d = 60c, we have t = 60c/(3c/2) = 40.
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Let s be the speed of the escalator and c be the speed of Clea. Using d = v t, the first statement can be translated to the equation d = 60c. The second statement can be translated to d = 24(c+s). Since the same distance is being covered in each scenario, we can set the two equations equal and solve for s to find s = 3c/2. The problem asks for the time it takes her to ride down the escalator. Since t = d/s and d = 60c, we have t = 60c/(3c/2) = 40.

Revision as of 16:43, 26 February 2012

Solution

Let s be the speed of the escalator and c be the speed of Clea. Using d = v t, the first statement can be translated to the equation d = 60c. The second statement can be translated to d = 24(c+s). Since the same distance is being covered in each scenario, we can set the two equations equal and solve for s to find s = 3c/2. The problem asks for the time it takes her to ride down the escalator. Since t = d/s and d = 60c, we have t = 60c/(3c/2) = 40.