Difference between revisions of "2008 iTest Problems/Problem 8"

(Created page with "== Problem == (story eliminated) Given the system of equations <center><math>2x + 3y + 3z = 8</math>, <math>3x + 2y + 3z = 808</math>, <math>3x + 3y + 2z = 80808</math>,</cente...")
 
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<math>3x + 3y + 2z = 80808</math>,</center>
 
<math>3x + 3y + 2z = 80808</math>,</center>
 
find <math>x+y+z</math>.
 
find <math>x+y+z</math>.
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==Solution==
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==See also==

Revision as of 18:09, 15 September 2012

Problem

(story eliminated)

Given the system of equations

$2x + 3y + 3z = 8$,

$3x + 2y + 3z = 808$,

$3x + 3y + 2z = 80808$,

find $x+y+z$.

Solution

See also