Difference between revisions of "2008 iTest Problems/Problem 8"
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==Solution== | ==Solution== | ||
| + | 2x + 3y + 3z = 8, | ||
| + | 3x + 2y + 3z = 808, | ||
| + | 3x + 3y + 2z = 80808, | ||
| + | |||
| + | The Solution can be found by summing the three equations to get: | ||
| + | |||
| + | 8x + 8y + 8z = 81624 | ||
| + | |||
| + | then solving for x+y+z, divide by 8 to get: | ||
| + | |||
| + | 10,203. | ||
==See also== | ==See also== | ||
Revision as of 23:28, 4 August 2014
Problem
(story eliminated)
Given the system of equations
,
,
,find 
.
Solution
2x + 3y + 3z = 8, 3x + 2y + 3z = 808, 3x + 3y + 2z = 80808,
The Solution can be found by summing the three equations to get:
8x + 8y + 8z = 81624
then solving for x+y+z, divide by 8 to get:
10,203.
