Difference between revisions of "2013 AMC 12A Problems/Problem 11"
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Revision as of 02:53, 7 February 2013
Let , and
. We want to find
, which is nothing but
.
Based on the fact that ,
, and
have the same perimeters, we can say the following:
Simplifying, we can find that
Since ,
.
After substitution, we find that , and
=
.
Again substituting, we find =
.
Therefore, =
, which is