Difference between revisions of "2013 AMC 12A Problems/Problem 4"

Revision as of 23:53, 7 February 2013

$\frac{2^{2014}+2^{2012}}{2^{2014}-2^{2012}}$

We can factor a ${2^{2012}}$ out of the numerator and denominator to obtain

$\frac{2^{2012}*(2^2+1)}{2^{2012}*(2^2-1)}$

The ${2^{2012}}$ cancels, so we get

$\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}$ , which is $C$

Revision as of 03:25, 7 February 2013 (view source) Epicwisdom (talk \| contribs) m (Wording) ← Older edit		Revision as of 23:53, 7 February 2013 (view source) Indianninja707 (talk \| contribs) Newer edit →
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	The <math>{2^{2012}}</math> cancels, so we get		The <math>{2^{2012}}</math> cancels, so we get

−	<math>\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}</math>, which is C	+	<math>\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}</math>, which is <math>C</math>