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| − | ==Problem==
| + | #REDIRECT [[2003 AMC 12B Problems/Problem 1]] |
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| − | Which of the following is the same as <math>\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</math>?
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| − | <math>\textbf{(A)}\ -1 \qquad
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| − | \textbf{(B)}\ -\frac23 \qquad
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| − | \textbf{(C)}\ \frac23 \qquad
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| − | \textbf{(D)}\ 1 \qquad
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| − | \textbf{(E)}\ \frac{14}{3}</math>
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| − | ==Solution==
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| − | We can rewrite the given fraction as:
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| − | <cmath>\frac{-3(2)+2(7)}{3(-3)+3(7)}=\frac{2(4)}{3(4)}=\frac{2}{3} \longrightarrow \boxed{\textbf{(C)}}</cmath>
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| − | ==See Also==
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| − | {{AMC10 box|year=2003|ab=B|before=First Question|num-a=2}}
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| − | [[Category: Introductory Algebra Problems]] | |
| − | {{MAA Notice}}
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