Difference between revisions of "AoPS Wiki:Sandbox"
(→Test 2) |
(→Test 3) |
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<math>\binom{\binom{3}{2}}{/binom{6}{2}}</math> | <math>\binom{\binom{3}{2}}{/binom{6}{2}}</math> | ||
<math>\sqrt{5}=50</math> | <math>\sqrt{5}=50</math> | ||
+ | HELLO WORLD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! | ||
==Test 5== | ==Test 5== |
Revision as of 11:24, 17 November 2013
Welcome to the sandbox, a location to test your newfound wiki-editing abilities.
Please note that all contributions here may be deleted periodically and without warning.
In the computer world, a sandbox is a place to test and experiment -- essentially, it's a place to play.
This is the AoPSWiki Sandbox. Feel free to experiment here.
Warning: anything you place here is subject to deletion without notice.
[This was deleted due to its inappropriateness.]
Test 1
Hi there yall
Test 2
Test
This is what epicness looks like.
BUT JEFFCHEN WOULDN'T KNOW
<asy2>unitsize(33);pair A,B,C,D,I;A=origin; B=1.6*right; C=1.6*dir(60); D=0.8*right;
I=incenter(A,B,C); draw(A--B--C--cycle);draw(incircle(A,B,C)); draw(C--D);
</asy2>
Test 3
Test 4.0000000000000000000000000000000000000000000000000000000000000000000
HELLO WORLD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Test 5
n1000 is editing this. yay! (Made better by AoPS)
Who loves me?
only
Test 6
NeoMathematicalKid was here. And he broke the line of asy diagrams.
$\begin{align*}\sum^4_{k=1}\left(\sum^k_{j=1}kj\right)&=\sum^4_{k=1}\left(k\sum^k_{j=1}j\right)\\ &=\sum^4_{k=1}\left(k(1+2+\cdots +k)\right)\\ &=\sum^4_{k=1}(k+2k+\cdots +k^2)\\ &=(1)+(2+4)+(3+6+9)+(4+8+12+16)\\ &=1+6+18+40\\ &=\boxed{65} \end{align*}$ (Error compiling LaTeX. Unknown error_msg) notice how the square root signs are becoming progressively less slanted... What is $\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{e^{1\pi\pi\sqrtpi}}}}}}+\cfrac{1}{1+\cfrac{1}{1+\cfrac{1}{1+\cfrac{1}{1+\cfrac{1}{1+\cfrac{1}{20}}}}}}$ (Error compiling LaTeX. Unknown error_msg)?!?! I got carried away.
Test 7
!
silentazn's trillion dollar question
bobthesmartypants's answer: There is not enough space in the observable universe to write this number down, so there s no valid answer. my answer: There's not enough matter in the observable universe to store this number in memory, so you don't know the valid answer.