Difference between revisions of "2014 AMC 12A Problems"

Revision as of 10:36, 7 February 2014

Problem 1

What is $10 \cdot \left(\tfrac{1}{2} + \tfrac{1}{5} + \tfrac{1}{10}\right)^{-1}?$

$\textbf{(A)}\ 3\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ \frac{25}{2}\qquad\textbf{(D)}}\ \frac{170}{3}\qquad\textbf{(E)}\ 170$ (Error compiling LaTeX. Unknown error_msg)

Problem 2

At the theater children get in for half price. The price for $5$ adult tickets and $4$ child tickets is $24.50$ . How much would $8$ adult tickets and $6$ child tickets cost?

$\textbf{(A) }35\qquad \textbf{(B) }38.50\qquad \textbf{(C) }40\qquad \textbf{(D) }42\qquad \textbf{(E) }42.50$

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

@@ Line 5: / Line 5: @@
 ==Problem 2==
-At the theater children get in for half price.  The price for <math>5</math> adult tickets and <math>4</math> child tickets is <math>&#036;24.50</math>.  How much would <math>8</math> adult tickets and <math>6</math> child tickets cost?
+At the theater children get in for half price.  The price for <math>5</math> adult tickets and <math>4</math> child tickets is <math>24.50</math>.  How much would <math>8</math> adult tickets and <math>6</math> child tickets cost?
-<math>\textbf{(A) }\text{&#036;}35\qquad
+<math>\textbf{(A) }35\qquad
-\textbf{(B) }&#036;38.50\qquad
+\textbf{(B) }38.50\qquad
-\textbf{(C) }&#036;40\qquad
+\textbf{(C) }40\qquad
-\textbf{(D) }&#036;42\qquad
+\textbf{(D) }42\qquad
-\textbf{(E) }&#036;42.50</math>
+\textbf{(E) }42.50</math>
 ==Problem 3==

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