Difference between revisions of "2014 AMC 12A Problems/Problem 5"

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==Problem==
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On an algebra quiz, <math>10\%</math> of the students scored <math>70</math> points, <math>35\%</math> scored <math>80</math> points, <math>30\%</math> scored <math>90</math> points, and the rest scored <math>100</math> points. What is the difference between the mean and median score of the students' scores on this quiz?
 
 
 
<math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}}\ 4\qquad\textbf{(E)}\ 5</math>
 
==Solution==
 
The mean can solved by the following. 10% of 70 is 7, 35% of 80 is 28, 30% of 90 is 27, and (100% - 10% - 35% - 30%) = 25%. 25% of 100 is 25. 7 + 28 + 27 + 25 = 87. <br>
 
The median can be solved by finding the score present at the 50% mark, which is 90.<br>
 
90-87 equals 3, which is (C) 3.
 

Revision as of 19:26, 7 February 2014

Deleted/merged because of duplicate