Difference between revisions of "2014 AIME I Problems/Problem 1"
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== Problem 1 == | == Problem 1 == | ||
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| + | The 8 eyelets for the lace of a sneaker all lie on a rectangle, four equally spaced on each of the longer sides. The rectangle has a width of 50 mm and a length of 80 mm. There is one eyelet at each vertex of the rectangle. The lace itself must pass between the vertex eyelets along a width side of the rectangle and then crisscross between successive eyelets until it reaches the two eyelets at the other width side of the rectrangle as shown. After passing through these final eyelets, each of the ends of the lace must extend at least 200 mm farther to allow a knot to be tied. Find the minimum length of the lace in millimeters. | ||
== Solution == | == Solution == | ||
Note that 6 right triangles are formed in the diagram, each with leg lengths <math>50</math> and <math>\frac{80}{3}</math>. By the Pythagoren theorem, the length of each of these hypotenuses is <math>\frac{170}{3}</math>, so the total length minus the two loop pieces is <math>340</math>. Accounting for the two loops, we find that our answer is <math>\boxed{740}</math>. | Note that 6 right triangles are formed in the diagram, each with leg lengths <math>50</math> and <math>\frac{80}{3}</math>. By the Pythagoren theorem, the length of each of these hypotenuses is <math>\frac{170}{3}</math>, so the total length minus the two loop pieces is <math>340</math>. Accounting for the two loops, we find that our answer is <math>\boxed{740}</math>. | ||
Revision as of 15:55, 14 March 2014
Problem 1
The 8 eyelets for the lace of a sneaker all lie on a rectangle, four equally spaced on each of the longer sides. The rectangle has a width of 50 mm and a length of 80 mm. There is one eyelet at each vertex of the rectangle. The lace itself must pass between the vertex eyelets along a width side of the rectangle and then crisscross between successive eyelets until it reaches the two eyelets at the other width side of the rectrangle as shown. After passing through these final eyelets, each of the ends of the lace must extend at least 200 mm farther to allow a knot to be tied. Find the minimum length of the lace in millimeters.
Solution
Note that 6 right triangles are formed in the diagram, each with leg lengths 
and 
. By the Pythagoren theorem, the length of each of these hypotenuses is 
, so the total length minus the two loop pieces is 
. Accounting for the two loops, we find that our answer is 
.
