Difference between revisions of "2014 AIME II Problems/Problem 15"
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− | + | ==Solution== | |
+ | Note that in base 2 <math>a_1</math> = 2, <math>a_10</math> = 3, <math>a_11</math> = 2 * 3 = 6, ..., <math>a_10010101</math> = 2 * 5 * 11 * 19 = 2090. Thus, t = 10010101 (base 2) = <math>\boxed{149}</math>. |
Revision as of 10:52, 28 March 2014
Solution
Note that in base 2 = 2,
= 3,
= 2 * 3 = 6, ...,
= 2 * 5 * 11 * 19 = 2090. Thus, t = 10010101 (base 2) =
.