Difference between revisions of "2006 AMC 12A Problems/Problem 13"
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== Problem == | == Problem == | ||
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+ | {{image}} | ||
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+ | The vertices of a <math>3-4-5</math> right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles? | ||
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+ | <math> \mathrm{(A) \ } 12\pi\qquad \mathrm{(B) \ } \frac{25\pi}{2}\qquad \mathrm{(C) \ } 13\pi\qquad \mathrm{(D) \ } \frac{27\pi}{2}\qquad \mathrm{(E) \ } 14\pi</math> | ||
== Solution == | == Solution == |
Revision as of 22:50, 10 July 2006
Problem
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The vertices of a right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles?