Difference between revisions of "1990 AHSME Problems/Problem 2"
(Created page with "== Problem == <math>\left(\frac{1}{4}\right)^{-\tfrac{1}{4}}=</math> <math>\text{(A) } -16\quad \text{(B) } -\sqrt{2}\quad \text{(C) } -\frac{1}{16}\quad \text{(D) } \frac{1}{2...") |
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== Solution == | == Solution == | ||
| − | <math>\fbox{E}</math> | + | <math>\left(\frac14\right)^{-\tfrac14}=4^{\tfrac14}=\sqrt[4]4=\sqrt{\sqrt4}=\sqrt2</math> which is <math>\fbox{E}</math> |
== See also == | == See also == | ||
Latest revision as of 02:38, 4 February 2016
Problem
Solution
![$\left(\frac14\right)^{-\tfrac14}=4^{\tfrac14}=\sqrt[4]4=\sqrt{\sqrt4}=\sqrt2$](http://latex.artofproblemsolving.com/5/1/e/51e8fbb0aba667673adc9ee7992fe140dfc35a67.png)
which is 
See also
| 1990 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
