Difference between revisions of "2015 AMC 10B Problems/Problem 2"
Pacific0408 (talk | contribs) (→Solution) |
Pacific0408 (talk | contribs) (→Solution) |
||
| Line 6: | Line 6: | ||
==Solution== | ==Solution== | ||
| − | Marie does her work twice in <math>1</math> hour and <math>40</math> minutes. Therefore, one task should take <math>50</math> minutes to finish. <math>50</math> minutes after <math>2:40</math> PM is <math>3:30</math> PM, so our answer is (B) | + | Marie does her work twice in <math>1</math> hour and <math>40</math> minutes. Therefore, one task should take <math>50</math> minutes to finish. <math>50</math> minutes after <math>2:40</math> PM is <math>3:30</math> PM, so our answer is <math>\boxed{\textbf{(B)}3:30PM}</math> |
Revision as of 18:34, 3 March 2015
Problem
Marie does three equally time-consuming tasks in a row without taking breaks. She begins the first task at 1:00 PM and finishes the second task at 2:40 PM. When does she finish the third task?
Solution
Marie does her work twice in 
hour and 
minutes. Therefore, one task should take 
minutes to finish. minutes after 
PM is 
PM, so our answer is 
